5(w+2)+4(w+1)=32

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Solution for 5(w+2)+4(w+1)=32 equation: 



5(w+2)+4(w+1)=32

We move all terms to the left:

5(w+2)+4(w+1)-(32)=0

We multiply parentheses

5w+4w+10+4-32=0

We add all the numbers together, and all the variables

9w-18=0

We move all terms containing w to the left, all other terms to the right

9w=18

w=18/9

w=2

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