5(w+2)+2=3(w-1)+1

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Solution for 5(w+2)+2=3(w-1)+1 equation: 



5(w+2)+2=3(w-1)+1

We move all terms to the left:

5(w+2)+2-(3(w-1)+1)=0

We multiply parentheses

5w-(3(w-1)+1)+10+2=0



We calculate terms in parentheses: -(3(w-1)+1), so:

3(w-1)+1

We multiply parentheses

3w-3+1

We add all the numbers together, and all the variables

3w-2

Back to the equation:

-(3w-2)



We add all the numbers together, and all the variables

5w-(3w-2)+12=0

We get rid of parentheses

5w-3w+2+12=0

We add all the numbers together, and all the variables

2w+14=0

We move all terms containing w to the left, all other terms to the right

2w=-14

w=-14/2

w=-7

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