5(v-5)=-4v+29

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Solution for 5(v-5)=-4v+29 equation: 



5(v-5)=-4v+29

We move all terms to the left:

5(v-5)-(-4v+29)=0

We multiply parentheses

5v-(-4v+29)-25=0

We get rid of parentheses

5v+4v-29-25=0

We add all the numbers together, and all the variables

9v-54=0

We move all terms containing v to the left, all other terms to the right

9v=54

v=54/9

v=6

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