5(v+7)=3-(-5v-32)

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Solution for 5(v+7)=3-(-5v-32) equation: 



5(v+7)=3-(-5v-32)

We move all terms to the left:

5(v+7)-(3-(-5v-32))=0

We multiply parentheses

5v-(3-(-5v-32))+35=0



We calculate terms in parentheses: -(3-(-5v-32)), so:

3-(-5v-32)

determiningTheFunctionDomain
-(-5v-32)+3

We get rid of parentheses

5v+32+3

We add all the numbers together, and all the variables

5v+35

Back to the equation:

-(5v+35)



We get rid of parentheses

5v-5v-35+35=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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