5(v+4)=-5(2v-1)+6v

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Solution for 5(v+4)=-5(2v-1)+6v equation: 



5(v+4)=-5(2v-1)+6v

We move all terms to the left:

5(v+4)-(-5(2v-1)+6v)=0

We multiply parentheses

5v-(-5(2v-1)+6v)+20=0



We calculate terms in parentheses: -(-5(2v-1)+6v), so:

-5(2v-1)+6v

We add all the numbers together, and all the variables

6v-5(2v-1)

We multiply parentheses

6v-10v+5

We add all the numbers together, and all the variables

-4v+5

Back to the equation:

-(-4v+5)



We get rid of parentheses

5v+4v-5+20=0

We add all the numbers together, and all the variables

9v+15=0

We move all terms containing v to the left, all other terms to the right

9v=-15

v=-15/9

v=-1+2/3

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