5(v+3)=-3(5v-4)+2v

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Solution for 5(v+3)=-3(5v-4)+2v equation: 



5(v+3)=-3(5v-4)+2v

We move all terms to the left:

5(v+3)-(-3(5v-4)+2v)=0

We multiply parentheses

5v-(-3(5v-4)+2v)+15=0



We calculate terms in parentheses: -(-3(5v-4)+2v), so:

-3(5v-4)+2v

We add all the numbers together, and all the variables

2v-3(5v-4)

We multiply parentheses

2v-15v+12

We add all the numbers together, and all the variables

-13v+12

Back to the equation:

-(-13v+12)



We get rid of parentheses

5v+13v-12+15=0

We add all the numbers together, and all the variables

18v+3=0

We move all terms containing v to the left, all other terms to the right

18v=-3

v=-3/18

v=-1/6

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