5(v+2)=-3(5v-2)+8v

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Solution for 5(v+2)=-3(5v-2)+8v equation: 



5(v+2)=-3(5v-2)+8v

We move all terms to the left:

5(v+2)-(-3(5v-2)+8v)=0

We multiply parentheses

5v-(-3(5v-2)+8v)+10=0



We calculate terms in parentheses: -(-3(5v-2)+8v), so:

-3(5v-2)+8v

We add all the numbers together, and all the variables

8v-3(5v-2)

We multiply parentheses

8v-15v+6

We add all the numbers together, and all the variables

-7v+6

Back to the equation:

-(-7v+6)



We get rid of parentheses

5v+7v-6+10=0

We add all the numbers together, and all the variables

12v+4=0

We move all terms containing v to the left, all other terms to the right

12v=-4

v=-4/12

v=-1/3

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