5(v+2)+1=3(v-1)+1

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Solution for 5(v+2)+1=3(v-1)+1 equation: 



5(v+2)+1=3(v-1)+1

We move all terms to the left:

5(v+2)+1-(3(v-1)+1)=0

We multiply parentheses

5v-(3(v-1)+1)+10+1=0



We calculate terms in parentheses: -(3(v-1)+1), so:

3(v-1)+1

We multiply parentheses

3v-3+1

We add all the numbers together, and all the variables

3v-2

Back to the equation:

-(3v-2)



We add all the numbers together, and all the variables

5v-(3v-2)+11=0

We get rid of parentheses

5v-3v+2+11=0

We add all the numbers together, and all the variables

2v+13=0

We move all terms containing v to the left, all other terms to the right

2v=-13

v=-13/2

v=-6+1/2

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