5(u+4)=-4(3u-3)+u

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Solution for 5(u+4)=-4(3u-3)+u equation: 



5(u+4)=-4(3u-3)+u

We move all terms to the left:

5(u+4)-(-4(3u-3)+u)=0

We multiply parentheses

5u-(-4(3u-3)+u)+20=0



We calculate terms in parentheses: -(-4(3u-3)+u), so:

-4(3u-3)+u

We add all the numbers together, and all the variables

u-4(3u-3)

We multiply parentheses

u-12u+12

We add all the numbers together, and all the variables

-11u+12

Back to the equation:

-(-11u+12)



We get rid of parentheses

5u+11u-12+20=0

We add all the numbers together, and all the variables

16u+8=0

We move all terms containing u to the left, all other terms to the right

16u=-8

u=-8/16

u=-1/2

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