5(t-3)+7t=6(2t+3)-1

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Solution for 5(t-3)+7t=6(2t+3)-1 equation: 



5(t-3)+7t=6(2t+3)-1

We move all terms to the left:

5(t-3)+7t-(6(2t+3)-1)=0

We add all the numbers together, and all the variables

7t+5(t-3)-(6(2t+3)-1)=0

We multiply parentheses

7t+5t-(6(2t+3)-1)-15=0



We calculate terms in parentheses: -(6(2t+3)-1), so:

6(2t+3)-1

We multiply parentheses

12t+18-1

We add all the numbers together, and all the variables

12t+17

Back to the equation:

-(12t+17)



We add all the numbers together, and all the variables

12t-(12t+17)-15=0

We get rid of parentheses

12t-12t-17-15=0

We add all the numbers together, and all the variables

-32!=0

There is no solution for this equation

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