5(t-2)+7t=4(3t+4)-12

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Solution for 5(t-2)+7t=4(3t+4)-12 equation:


Simplifying
5(t + -2) + 7t = 4(3t + 4) + -12

Reorder the terms:
5(-2 + t) + 7t = 4(3t + 4) + -12
(-2 * 5 + t * 5) + 7t = 4(3t + 4) + -12
(-10 + 5t) + 7t = 4(3t + 4) + -12

Combine like terms: 5t + 7t = 12t
-10 + 12t = 4(3t + 4) + -12

Reorder the terms:
-10 + 12t = 4(4 + 3t) + -12
-10 + 12t = (4 * 4 + 3t * 4) + -12
-10 + 12t = (16 + 12t) + -12

Reorder the terms:
-10 + 12t = 16 + -12 + 12t

Combine like terms: 16 + -12 = 4
-10 + 12t = 4 + 12t

Add '-12t' to each side of the equation.
-10 + 12t + -12t = 4 + 12t + -12t

Combine like terms: 12t + -12t = 0
-10 + 0 = 4 + 12t + -12t
-10 = 4 + 12t + -12t

Combine like terms: 12t + -12t = 0
-10 = 4 + 0
-10 = 4

Solving
-10 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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