5(t-1)=-5(t+4)+5

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Solution for 5(t-1)=-5(t+4)+5 equation: 



5(t-1)=-5(t+4)+5

We move all terms to the left:

5(t-1)-(-5(t+4)+5)=0

We multiply parentheses

5t-(-5(t+4)+5)-5=0



We calculate terms in parentheses: -(-5(t+4)+5), so:

-5(t+4)+5

We multiply parentheses

-5t-20+5

We add all the numbers together, and all the variables

-5t-15

Back to the equation:

-(-5t-15)



We get rid of parentheses

5t+5t+15-5=0

We add all the numbers together, and all the variables

10t+10=0

We move all terms containing t to the left, all other terms to the right

10t=-10

t=-10/10

t=-1

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