5(t+2)-2t=8-(t-7)

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Solution for 5(t+2)-2t=8-(t-7) equation: 



5(t+2)-2t=8-(t-7)

We move all terms to the left:

5(t+2)-2t-(8-(t-7))=0

We add all the numbers together, and all the variables

-2t+5(t+2)-(8-(t-7))=0

We multiply parentheses

-2t+5t-(8-(t-7))+10=0



We calculate terms in parentheses: -(8-(t-7)), so:

8-(t-7)

determiningTheFunctionDomain
-(t-7)+8

We get rid of parentheses

-t+7+8

We add all the numbers together, and all the variables

-1t+15

Back to the equation:

-(-1t+15)



We add all the numbers together, and all the variables

3t-(-1t+15)+10=0

We get rid of parentheses

3t+1t-15+10=0

We add all the numbers together, and all the variables

4t-5=0

We move all terms containing t to the left, all other terms to the right

4t=5

t=5/4

t=1+1/4

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