5(r-7)=5r-35

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Solution for 5(r-7)=5r-35 equation: 



5(r-7)=5r-35

We move all terms to the left:

5(r-7)-(5r-35)=0

We multiply parentheses

5r-(5r-35)-35=0

We get rid of parentheses

5r-5r+35-35=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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