5(r-3)=10(r/2-30)

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Solution for 5(r-3)=10(r/2-30) equation: 


r in (-oo:+oo)

5*(r-3) = 10*(r/2-30) // - 10*(r/2-30)

5*(r-3)-(10*(r/2-30)) = 0

5*(r-3)-10*(r/2-30) = 0

5*(r-3)-10*(1/2*r-30) = 0

5*(r-3)-10*(1/2*r-30) = 0

285 = 0

285 = 0

285 = 0

r belongs to the empty set

r belongs to the empty set

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