5(r-3)-4(r-1)=2(r+7)

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Solution for 5(r-3)-4(r-1)=2(r+7) equation:


Simplifying
5(r + -3) + -4(r + -1) = 2(r + 7)

Reorder the terms:
5(-3 + r) + -4(r + -1) = 2(r + 7)
(-3 * 5 + r * 5) + -4(r + -1) = 2(r + 7)
(-15 + 5r) + -4(r + -1) = 2(r + 7)

Reorder the terms:
-15 + 5r + -4(-1 + r) = 2(r + 7)
-15 + 5r + (-1 * -4 + r * -4) = 2(r + 7)
-15 + 5r + (4 + -4r) = 2(r + 7)

Reorder the terms:
-15 + 4 + 5r + -4r = 2(r + 7)

Combine like terms: -15 + 4 = -11
-11 + 5r + -4r = 2(r + 7)

Combine like terms: 5r + -4r = 1r
-11 + 1r = 2(r + 7)

Reorder the terms:
-11 + 1r = 2(7 + r)
-11 + 1r = (7 * 2 + r * 2)
-11 + 1r = (14 + 2r)

Solving
-11 + 1r = 14 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-11 + 1r + -2r = 14 + 2r + -2r

Combine like terms: 1r + -2r = -1r
-11 + -1r = 14 + 2r + -2r

Combine like terms: 2r + -2r = 0
-11 + -1r = 14 + 0
-11 + -1r = 14

Add '11' to each side of the equation.
-11 + 11 + -1r = 14 + 11

Combine like terms: -11 + 11 = 0
0 + -1r = 14 + 11
-1r = 14 + 11

Combine like terms: 14 + 11 = 25
-1r = 25

Divide each side by '-1'.
r = -25

Simplifying
r = -25

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