5(r-3)-17+r=2(r+8)-12

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Solution for 5(r-3)-17+r=2(r+8)-12 equation: 



5(r-3)-17+r=2(r+8)-12

We move all terms to the left:

5(r-3)-17+r-(2(r+8)-12)=0

We add all the numbers together, and all the variables

r+5(r-3)-(2(r+8)-12)-17=0

We multiply parentheses

r+5r-(2(r+8)-12)-15-17=0



We calculate terms in parentheses: -(2(r+8)-12), so:

2(r+8)-12

We multiply parentheses

2r+16-12

We add all the numbers together, and all the variables

2r+4

Back to the equation:

-(2r+4)



We add all the numbers together, and all the variables

6r-(2r+4)-32=0

We get rid of parentheses

6r-2r-4-32=0

We add all the numbers together, and all the variables

4r-36=0

We move all terms containing r to the left, all other terms to the right

4r=36

r=36/4

r=9

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