5(r-3)(r+3)=0

Solution for 5(r-3)(r+3)=0 equation:

Simplifying
5(r + -3)(r + 3) = 0

Reorder the terms:
5(-3 + r)(r + 3) = 0

Reorder the terms:
5(-3 + r)(3 + r) = 0

Multiply (-3 + r) * (3 + r)
5(-3(3 + r) + r(3 + r)) = 0
5((3 * -3 + r * -3) + r(3 + r)) = 0
5((-9 + -3r) + r(3 + r)) = 0
5(-9 + -3r + (3 * r + r * r)) = 0
5(-9 + -3r + (3r + r2)) = 0

Combine like terms: -3r + 3r = 0
5(-9 + 0 + r2) = 0
5(-9 + r2) = 0
(-9 * 5 + r2 * 5) = 0
(-45 + 5r2) = 0

Solving
-45 + 5r2 = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '45' to each side of the equation.
-45 + 45 + 5r2 = 0 + 45

Combine like terms: -45 + 45 = 0
0 + 5r2 = 0 + 45
5r2 = 0 + 45

Combine like terms: 0 + 45 = 45
5r2 = 45

Divide each side by '5'.
r2 = 9

Simplifying
r2 = 9

Take the square root of each side:
r = {-3, 3}