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5(r-1)=2(r+2)+4r
We move all terms to the left:
5(r-1)-(2(r+2)+4r)=0
We multiply parentheses
5r-(2(r+2)+4r)-5=0
We calculate terms in parentheses: -(2(r+2)+4r), so:We get rid of parentheses
2(r+2)+4r
We add all the numbers together, and all the variables
4r+2(r+2)
We multiply parentheses
4r+2r+4
We add all the numbers together, and all the variables
6r+4
Back to the equation:
-(6r+4)
5r-6r-4-5=0
We add all the numbers together, and all the variables
-1r-9=0
We move all terms containing r to the left, all other terms to the right
-r=9
r=9/-1
r=-9
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