5(p+4)=4(p-2)+p+28

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Solution for 5(p+4)=4(p-2)+p+28 equation: 



5(p+4)=4(p-2)+p+28

We move all terms to the left:

5(p+4)-(4(p-2)+p+28)=0

We multiply parentheses

5p-(4(p-2)+p+28)+20=0



We calculate terms in parentheses: -(4(p-2)+p+28), so:

4(p-2)+p+28

We add all the numbers together, and all the variables

p+4(p-2)+28

We multiply parentheses

p+4p-8+28

We add all the numbers together, and all the variables

5p+20

Back to the equation:

-(5p+20)



We get rid of parentheses

5p-5p-20+20=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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