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x in (-oo:+oo)
5*(n+2) = (3/5)*(10*m+5) // - (3/5)*(10*m+5)
5*(n+2)-((3/5)*(10*m+5)) = 0
5*(n+2)+(-3/5)*(10*m+5) = 0
5*(n+2)-3/5*(10*m+5) = 0
5*(n+2)-3/5*(10*m+5) = 0
5*n-6*m+7 = 0
5*n-6*m+7 = 0
x belongs to the empty set
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