5(n+2)=3-5(5+10n)

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Solution for 5(n+2)=3-5(5+10n) equation: 



5(n+2)=3-5(5+10n)

We move all terms to the left:

5(n+2)-(3-5(5+10n))=0

We add all the numbers together, and all the variables

5(n+2)-(3-5(10n+5))=0

We multiply parentheses

5n-(3-5(10n+5))+10=0



We calculate terms in parentheses: -(3-5(10n+5)), so:

3-5(10n+5)

determiningTheFunctionDomain
-5(10n+5)+3

We multiply parentheses

-50n-25+3

We add all the numbers together, and all the variables

-50n-22

Back to the equation:

-(-50n-22)



We get rid of parentheses

5n+50n+22+10=0

We add all the numbers together, and all the variables

55n+32=0

We move all terms containing n to the left, all other terms to the right

55n=-32

n=-32/55

n=-32/55

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