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5(n+2)=1/2(-9n+8)
We move all terms to the left:
5(n+2)-(1/2(-9n+8))=0
Domain of the equation: 2(-9n+8))!=0We multiply parentheses
n∈R
5n-(1/2(-9n+8))+10=0
We multiply all the terms by the denominator
5n*2(-9n+8))-(1+10*2(-9n+8))=0
Wy multiply elements
10n^2(-+20n(-=0
We use the square of the difference formula
10n^2(-20n(-=0
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