5(n+12)=32-4n

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Solution for 5(n+12)=32-4n equation: 



5(n+12)=32-4n

We move all terms to the left:

5(n+12)-(32-4n)=0

We add all the numbers together, and all the variables

5(n+12)-(-4n+32)=0

We multiply parentheses

5n-(-4n+32)+60=0

We get rid of parentheses

5n+4n-32+60=0

We add all the numbers together, and all the variables

9n+28=0

We move all terms containing n to the left, all other terms to the right

9n=-28

n=-28/9

n=-3+1/9

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