5(n+1)=-5(n+2)+5

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Solution for 5(n+1)=-5(n+2)+5 equation: 



5(n+1)=-5(n+2)+5

We move all terms to the left:

5(n+1)-(-5(n+2)+5)=0

We multiply parentheses

5n-(-5(n+2)+5)+5=0



We calculate terms in parentheses: -(-5(n+2)+5), so:

-5(n+2)+5

We multiply parentheses

-5n-10+5

We add all the numbers together, and all the variables

-5n-5

Back to the equation:

-(-5n-5)



We get rid of parentheses

5n+5n+5+5=0

We add all the numbers together, and all the variables

10n+10=0

We move all terms containing n to the left, all other terms to the right

10n=-10

n=-10/10

n=-1

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