5(m-3)-7=-2(m+4)+1

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Solution for 5(m-3)-7=-2(m+4)+1 equation: 



5(m-3)-7=-2(m+4)+1

We move all terms to the left:

5(m-3)-7-(-2(m+4)+1)=0

We multiply parentheses

5m-(-2(m+4)+1)-15-7=0



We calculate terms in parentheses: -(-2(m+4)+1), so:

-2(m+4)+1

We multiply parentheses

-2m-8+1

We add all the numbers together, and all the variables

-2m-7

Back to the equation:

-(-2m-7)



We add all the numbers together, and all the variables

5m-(-2m-7)-22=0

We get rid of parentheses

5m+2m+7-22=0

We add all the numbers together, and all the variables

7m-15=0

We move all terms containing m to the left, all other terms to the right

7m=15

m=15/7

m=2+1/7

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