5(m+3)=2(11-m)

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Solution for 5(m+3)=2(11-m) equation: 



5(m+3)=2(11-m)

We move all terms to the left:

5(m+3)-(2(11-m))=0

We add all the numbers together, and all the variables

5(m+3)-(2(-1m+11))=0

We multiply parentheses

5m-(2(-1m+11))+15=0



We calculate terms in parentheses: -(2(-1m+11)), so:

2(-1m+11)

We multiply parentheses

-2m+22

Back to the equation:

-(-2m+22)



We get rid of parentheses

5m+2m-22+15=0

We add all the numbers together, and all the variables

7m-7=0

We move all terms containing m to the left, all other terms to the right

7m=7

m=7/7

m=1

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