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5(m+2)=4-6(m-2)
We move all terms to the left:
5(m+2)-(4-6(m-2))=0
We multiply parentheses
5m-(4-6(m-2))+10=0
We calculate terms in parentheses: -(4-6(m-2)), so:We get rid of parentheses
4-6(m-2)
determiningTheFunctionDomain -6(m-2)+4
We multiply parentheses
-6m+12+4
We add all the numbers together, and all the variables
-6m+16
Back to the equation:
-(-6m+16)
5m+6m-16+10=0
We add all the numbers together, and all the variables
11m-6=0
We move all terms containing m to the left, all other terms to the right
11m=6
m=6/11
m=6/11
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