5(m+1)=2(10+m)

Solution for 5(m+1)=2(10+m) equation:

5(m+1)=2(10+m)

We move all terms to the left:

5(m+1)-(2(10+m))=0

We add all the numbers together, and all the variables

5(m+1)-(2(m+10))=0

We multiply parentheses

5m-(2(m+10))+5=0


We calculate terms in parentheses: -(2(m+10)), so:

2(m+10)

We multiply parentheses

2m+20

Back to the equation:

-(2m+20)


We get rid of parentheses

5m-2m-20+5=0

We add all the numbers together, and all the variables

3m-15=0

We move all terms containing m to the left, all other terms to the right

3m=15

m=15/3

m=5