5(m+1)=(m-1)

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Solution for 5(m+1)=(m-1) equation: 



5(m+1)=(m-1)

We move all terms to the left:

5(m+1)-((m-1))=0

We multiply parentheses

5m-((m-1))+5=0



We calculate terms in parentheses: -((m-1)), so:

(m-1)

We get rid of parentheses

m-1

Back to the equation:

-(m-1)



We get rid of parentheses

5m-m+1+5=0

We add all the numbers together, and all the variables

4m+6=0

We move all terms containing m to the left, all other terms to the right

4m=-6

m=-6/4

m=-1+1/2

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