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5(k-3)-5=3k-(2k-3)
We move all terms to the left:
5(k-3)-5-(3k-(2k-3))=0
We multiply parentheses
5k-(3k-(2k-3))-15-5=0
We calculate terms in parentheses: -(3k-(2k-3)), so:We add all the numbers together, and all the variables
3k-(2k-3)
We get rid of parentheses
3k-2k+3
We add all the numbers together, and all the variables
k+3
Back to the equation:
-(k+3)
5k-(k+3)-20=0
We get rid of parentheses
5k-k-3-20=0
We add all the numbers together, and all the variables
4k-23=0
We move all terms containing k to the left, all other terms to the right
4k=23
k=23/4
k=5+3/4
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