5(k+2)-7=13+(4-k)

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Solution for 5(k+2)-7=13+(4-k) equation: 



5(k+2)-7=13+(4-k)

We move all terms to the left:

5(k+2)-7-(13+(4-k))=0

We add all the numbers together, and all the variables

5(k+2)-(13+(-1k+4))-7=0

We multiply parentheses

5k-(13+(-1k+4))+10-7=0



We calculate terms in parentheses: -(13+(-1k+4)), so:

13+(-1k+4)

determiningTheFunctionDomain
(-1k+4)+13

We get rid of parentheses

-1k+4+13

We add all the numbers together, and all the variables

-1k+17

Back to the equation:

-(-1k+17)



We add all the numbers together, and all the variables

5k-(-1k+17)+3=0

We get rid of parentheses

5k+1k-17+3=0

We add all the numbers together, and all the variables

6k-14=0

We move all terms containing k to the left, all other terms to the right

6k=14

k=14/6

k=2+1/3

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