5(k+2)-7/6=13-(4-k)/9

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Solution for 5(k+2)-7/6=13-(4-k)/9 equation: 


k in (-oo:+oo)

5*(k+2)-(7/6) = 13-((4-k)/9) // - 13-((4-k)/9)

5*(k+2)+(4-k)/9-(7/6)-13 = 0

5*(k+2)+(4-k)/9-7/6-13 = 0

(5*6*9*(k+2))/(6*9)+(6*(4-k))/(6*9)+(-7*9)/(6*9)+(-13*6*9)/(6*9) = 0

5*6*9*(k+2)+6*(4-k)-7*9-13*6*9 = 0

264*k-702-63+564 = 0

264*k-702+501 = 0

264*k-201 = 0

(264*k-201)/(6*9) = 0

(264*k-201)/(6*9) = 0 // * 6*9

264*k-201 = 0

264*k-201 = 0 // + 201

264*k = 201 // : 264

k = 201/264

k = 67/88

k = 67/88

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