5(j-4)+1j=-8

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Solution for 5(j-4)+1j=-8 equation: 



5(j-4)+1j=-8

We move all terms to the left:

5(j-4)+1j-(-8)=0

We add all the numbers together, and all the variables

j+5(j-4)+8=0

We multiply parentheses

j+5j-20+8=0

We add all the numbers together, and all the variables

6j-12=0

We move all terms containing j to the left, all other terms to the right

6j=12

j=12/6

j=2

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