5(j-3)=10(j-2)

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Solution for 5(j-3)=10(j-2) equation:


Simplifying
5(j + -3) = 10(j + -2)

Reorder the terms:
5(-3 + j) = 10(j + -2)
(-3 * 5 + j * 5) = 10(j + -2)
(-15 + 5j) = 10(j + -2)

Reorder the terms:
-15 + 5j = 10(-2 + j)
-15 + 5j = (-2 * 10 + j * 10)
-15 + 5j = (-20 + 10j)

Solving
-15 + 5j = -20 + 10j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-10j' to each side of the equation.
-15 + 5j + -10j = -20 + 10j + -10j

Combine like terms: 5j + -10j = -5j
-15 + -5j = -20 + 10j + -10j

Combine like terms: 10j + -10j = 0
-15 + -5j = -20 + 0
-15 + -5j = -20

Add '15' to each side of the equation.
-15 + 15 + -5j = -20 + 15

Combine like terms: -15 + 15 = 0
0 + -5j = -20 + 15
-5j = -20 + 15

Combine like terms: -20 + 15 = -5
-5j = -5

Divide each side by '-5'.
j = 1

Simplifying
j = 1

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