5(j+2)=j+6(j-3)

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Solution for 5(j+2)=j+6(j-3) equation: 


Simplifying
5(j + 2) = j + 6(j + -3)

Reorder the terms:
5(2 + j) = j + 6(j + -3)
(2 * 5 + j * 5) = j + 6(j + -3)
(10 + 5j) = j + 6(j + -3)

Reorder the terms:
10 + 5j = j + 6(-3 + j)
10 + 5j = j + (-3 * 6 + j * 6)
10 + 5j = j + (-18 + 6j)

Reorder the terms:
10 + 5j = -18 + j + 6j

Combine like terms: j + 6j = 7j
10 + 5j = -18 + 7j

Solving
10 + 5j = -18 + 7j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-7j' to each side of the equation.
10 + 5j + -7j = -18 + 7j + -7j

Combine like terms: 5j + -7j = -2j
10 + -2j = -18 + 7j + -7j

Combine like terms: 7j + -7j = 0
10 + -2j = -18 + 0
10 + -2j = -18

Add '-10' to each side of the equation.
10 + -10 + -2j = -18 + -10

Combine like terms: 10 + -10 = 0
0 + -2j = -18 + -10
-2j = -18 + -10

Combine like terms: -18 + -10 = -28
-2j = -28

Divide each side by '-2'.
j = 14

Simplifying
j = 14

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