5(i+2)=8i-1

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Solution for 5(i+2)=8i-1 equation: 



5(i+2)=8i-1

We move all terms to the left:

5(i+2)-(8i-1)=0

We multiply parentheses

5i-(8i-1)+10=0

We get rid of parentheses

5i-8i+1+10=0

We add all the numbers together, and all the variables

-3i+11=0

We move all terms containing i to the left, all other terms to the right

-3i=-11

i=-11/-3

i=3+2/3

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