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5(h+2)=2(3-h)
We move all terms to the left:
5(h+2)-(2(3-h))=0
We add all the numbers together, and all the variables
5(h+2)-(2(-1h+3))=0
We multiply parentheses
5h-(2(-1h+3))+10=0
We calculate terms in parentheses: -(2(-1h+3)), so:We get rid of parentheses
2(-1h+3)
We multiply parentheses
-2h+6
Back to the equation:
-(-2h+6)
5h+2h-6+10=0
We add all the numbers together, and all the variables
7h+4=0
We move all terms containing h to the left, all other terms to the right
7h=-4
h=-4/7
h=-4/7
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