5(h+2)=(h-1)

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Solution for 5(h+2)=(h-1) equation: 



5(h+2)=(h-1)

We move all terms to the left:

5(h+2)-((h-1))=0

We multiply parentheses

5h-((h-1))+10=0



We calculate terms in parentheses: -((h-1)), so:

(h-1)

We get rid of parentheses

h-1

Back to the equation:

-(h-1)



We get rid of parentheses

5h-h+1+10=0

We add all the numbers together, and all the variables

4h+11=0

We move all terms containing h to the left, all other terms to the right

4h=-11

h=-11/4

h=-2+3/4

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