5(g-4)+g=6(g-1)

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Solution for 5(g-4)+g=6(g-1) equation: 



5(g-4)+g=6(g-1)

We move all terms to the left:

5(g-4)+g-(6(g-1))=0

We add all the numbers together, and all the variables

g+5(g-4)-(6(g-1))=0

We multiply parentheses

g+5g-(6(g-1))-20=0



We calculate terms in parentheses: -(6(g-1)), so:

6(g-1)

We multiply parentheses

6g-6

Back to the equation:

-(6g-6)



We add all the numbers together, and all the variables

6g-(6g-6)-20=0

We get rid of parentheses

6g-6g+6-20=0

We add all the numbers together, and all the variables

-14!=0

There is no solution for this equation

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