5(f-5)=3(f+1)

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Solution for 5(f-5)=3(f+1) equation: 



5(f-5)=3(f+1)

We move all terms to the left:

5(f-5)-(3(f+1))=0

We multiply parentheses

5f-(3(f+1))-25=0



We calculate terms in parentheses: -(3(f+1)), so:

3(f+1)

We multiply parentheses

3f+3

Back to the equation:

-(3f+3)



We get rid of parentheses

5f-3f-3-25=0

We add all the numbers together, and all the variables

2f-28=0

We move all terms containing f to the left, all other terms to the right

2f=28

f=28/2

f=14

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