5(f+3)=20

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Solution for 5(f+3)=20 equation: 



5(f+3)=20

We move all terms to the left:

5(f+3)-(20)=0

We multiply parentheses

5f+15-20=0

We add all the numbers together, and all the variables

5f-5=0

We move all terms containing f to the left, all other terms to the right

5f=5

f=5/5

f=1

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