5(d+4)+2=2(d-2)-4

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Solution for 5(d+4)+2=2(d-2)-4 equation: 



5(d+4)+2=2(d-2)-4

We move all terms to the left:

5(d+4)+2-(2(d-2)-4)=0

We multiply parentheses

5d-(2(d-2)-4)+20+2=0



We calculate terms in parentheses: -(2(d-2)-4), so:

2(d-2)-4

We multiply parentheses

2d-4-4

We add all the numbers together, and all the variables

2d-8

Back to the equation:

-(2d-8)



We add all the numbers together, and all the variables

5d-(2d-8)+22=0

We get rid of parentheses

5d-2d+8+22=0

We add all the numbers together, and all the variables

3d+30=0

We move all terms containing d to the left, all other terms to the right

3d=-30

d=-30/3

d=-10

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