5(d+1)-8=3(1+d)+2d

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Solution for 5(d+1)-8=3(1+d)+2d equation: 



5(d+1)-8=3(1+d)+2d

We move all terms to the left:

5(d+1)-8-(3(1+d)+2d)=0

We add all the numbers together, and all the variables

5(d+1)-(3(d+1)+2d)-8=0

We multiply parentheses

5d-(3(d+1)+2d)+5-8=0



We calculate terms in parentheses: -(3(d+1)+2d), so:

3(d+1)+2d

We add all the numbers together, and all the variables

2d+3(d+1)

We multiply parentheses

2d+3d+3

We add all the numbers together, and all the variables

5d+3

Back to the equation:

-(5d+3)



We add all the numbers together, and all the variables

5d-(5d+3)-3=0

We get rid of parentheses

5d-5d-3-3=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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