5(c-4)+6=3+c-17

Solution for 5(c-4)+6=3+c-17 equation:

Simplifying
5(c + -4) + 6 = 3 + c + -17

Reorder the terms:
5(-4 + c) + 6 = 3 + c + -17
(-4 * 5 + c * 5) + 6 = 3 + c + -17
(-20 + 5c) + 6 = 3 + c + -17

Reorder the terms:
-20 + 6 + 5c = 3 + c + -17

Combine like terms: -20 + 6 = -14
-14 + 5c = 3 + c + -17

Reorder the terms:
-14 + 5c = 3 + -17 + c

Combine like terms: 3 + -17 = -14
-14 + 5c = -14 + c

Add '14' to each side of the equation.
-14 + 14 + 5c = -14 + 14 + c

Combine like terms: -14 + 14 = 0
0 + 5c = -14 + 14 + c
5c = -14 + 14 + c

Combine like terms: -14 + 14 = 0
5c = 0 + c
5c = c

Solving
5c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
5c + -1c = c + -1c

Combine like terms: 5c + -1c = 4c
4c = c + -1c

Combine like terms: c + -1c = 0
4c = 0

Divide each side by '4'.
c = 0

Simplifying
c = 0