5(c-3)=2(c+3)

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Solution for 5(c-3)=2(c+3) equation: 



5(c-3)=2(c+3)

We move all terms to the left:

5(c-3)-(2(c+3))=0

We multiply parentheses

5c-(2(c+3))-15=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We get rid of parentheses

5c-2c-6-15=0

We add all the numbers together, and all the variables

3c-21=0

We move all terms containing c to the left, all other terms to the right

3c=21

c=21/3

c=7

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