5(c-2)=2(c+1)

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Solution for 5(c-2)=2(c+1) equation:


Simplifying
5(c + -2) = 2(c + 1)

Reorder the terms:
5(-2 + c) = 2(c + 1)
(-2 * 5 + c * 5) = 2(c + 1)
(-10 + 5c) = 2(c + 1)

Reorder the terms:
-10 + 5c = 2(1 + c)
-10 + 5c = (1 * 2 + c * 2)
-10 + 5c = (2 + 2c)

Solving
-10 + 5c = 2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-10 + 5c + -2c = 2 + 2c + -2c

Combine like terms: 5c + -2c = 3c
-10 + 3c = 2 + 2c + -2c

Combine like terms: 2c + -2c = 0
-10 + 3c = 2 + 0
-10 + 3c = 2

Add '10' to each side of the equation.
-10 + 10 + 3c = 2 + 10

Combine like terms: -10 + 10 = 0
0 + 3c = 2 + 10
3c = 2 + 10

Combine like terms: 2 + 10 = 12
3c = 12

Divide each side by '3'.
c = 4

Simplifying
c = 4

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