5(c+3)=15+2(2c-+)

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Solution for 5(c+3)=15+2(2c-+) equation: 



5(c+3)=15+2(2c-+)

We move all terms to the left:

5(c+3)-(15+2(2c-+))=0

We add all the numbers together, and all the variables

5(c+3)-(15+2(+2c))=0

We multiply parentheses

5c-(15+2(+2c))+15=0



We calculate terms in parentheses: -(15+2(+2c)), so:

15+2(+2c)

determiningTheFunctionDomain
2(+2c)+15

We multiply parentheses

4c+15

Back to the equation:

-(4c+15)



We get rid of parentheses

5c-4c-15+15=0

We add all the numbers together, and all the variables

c=0

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