5(c+2)=7(c-4)

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Solution for 5(c+2)=7(c-4) equation:


Simplifying
5(c + 2) = 7(c + -4)

Reorder the terms:
5(2 + c) = 7(c + -4)
(2 * 5 + c * 5) = 7(c + -4)
(10 + 5c) = 7(c + -4)

Reorder the terms:
10 + 5c = 7(-4 + c)
10 + 5c = (-4 * 7 + c * 7)
10 + 5c = (-28 + 7c)

Solving
10 + 5c = -28 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
10 + 5c + -7c = -28 + 7c + -7c

Combine like terms: 5c + -7c = -2c
10 + -2c = -28 + 7c + -7c

Combine like terms: 7c + -7c = 0
10 + -2c = -28 + 0
10 + -2c = -28

Add '-10' to each side of the equation.
10 + -10 + -2c = -28 + -10

Combine like terms: 10 + -10 = 0
0 + -2c = -28 + -10
-2c = -28 + -10

Combine like terms: -28 + -10 = -38
-2c = -38

Divide each side by '-2'.
c = 19

Simplifying
c = 19

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