5(c+2)=20-5c

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Solution for 5(c+2)=20-5c equation: 



5(c+2)=20-5c

We move all terms to the left:

5(c+2)-(20-5c)=0

We add all the numbers together, and all the variables

5(c+2)-(-5c+20)=0

We multiply parentheses

5c-(-5c+20)+10=0

We get rid of parentheses

5c+5c-20+10=0

We add all the numbers together, and all the variables

10c-10=0

We move all terms containing c to the left, all other terms to the right

10c=10

c=10/10

c=1

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